CC/BCC का full form क्या होता है?

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अगर `A+B+C=pi` , साबित करो `cotA+cotB+cotC-cos e cAdotcos e cBdotcos e cC=cotAdotcotBdotcotCdot`
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वो दिखाओ: `|b+cc+a a+b q+r r+p p+q y+z z+xx+y|=2|a b c p q r x y z|`
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निर्धारकों के गुणों का उपयोग करके। वो दिखाओ: `|a^2+1a b a c a bb^2+1b cc a c b c^2+1|=(1+a^2+b^2+b^2)`
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निर्धारकों की संपत्ति का उपयोग और विस्तार के बिना, साबित करें कि: `|a-bb-cc-a b-cc-a a-b c-a a-bb-c|=0`
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