Find the sum of all natural numbers between 100 and 1000 which are divisible by 11 is : (a) 44,550 (b) 66,770 (c) 55,440 (d) 33,440

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next to 100 the no divisible by 11=110

so nos are 110,121.....................990

this an AP  a=110,d=10,l=990

990=110+(n-1)11

880=(n-1)11

n-1=80

n=81

sum of no

sn=81/2(a+l+=81/2*(110+990)

=81/2*1100=81*550

=44550

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1 answer asked Feb 11, 2019 in राजनीतिक शास्त्र by anonymous
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