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solve this $(2t^4 + 3t^3 - 2t^2 - 9t - 12) ÷( t^2 - 3)$

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Check whether the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial : `t^2-3,""""2t^4+3t^3-2t^2-9t-12`
जांचें कि पहला बहुपद पहले बहुपद द्वारा दूसरे बहुपद को विभाजित करके दूसरे बहुपद का एक कारक है: `t^2-3,""""2t^4+3t^3-2t^2-9t-12`
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वक्र के लिए स्पर्शक की ढलान `x=t^2+3t-8,` `y=2t^2-2t-5` बिंदु पर `(2, " "1)` एक है) `(22)/7` (बी) `6/7` (सी) `7/6` (डी) `(-6)/7`
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The solution set of the equation `4 sintheta.costheta-2costheta-2sqrt(3)sintheta +sqrt(3)=0` in the interval (0, 2T)ist (B) 13, 3 j (A) 4 4 (C) 4 3, 3 (D) All solutions of the equation 2 sino tann 0 ere obtained by taking a integral valuessof m and n in
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निम्नलिखित पंक्तियों के बीच सबसे छोटी दूरी खोजें जिनके वेक्टर समीकरण हैं: ` vec r=(1-t) hat i+(t-2) hat j+(3-2t) hat k` तथा ` vec r=(s+1) hat i+(2s-1) hat j- (2s+1) hat k` ।
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का मूल्य पाएं `x` ऐसा है कि `((x+alpha)^n-(x+beta)^n)/(alpha-beta)=(sin (ntheta))/(sin^n theta)` , कहा पे `alpha` तथा `beta` समीकरण की जड़ें हैं `t^2-2t+2=0` ।
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रैखिक समीकरणों को सरल और हल करें। `3(t-3)=5(2t+1)`
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निम्न में से प्रत्येक बहुपद के लिए पी (0), पी (1) और पी (2) खोजें: (i) `p(y)=y^2-y+1` (II) `p(t)=2+t+2t^2-t^3` (Iii) `p(x)=x^3` (Iv) `p(x)=(x-1)(x+1)`
0 answers asked Sep 2, 2020 in General Knowledge by anonymous
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0 answers asked Sep 2, 2020 in General Knowledge by anonymous
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0 answers asked Sep 7, 2020 in General Knowledge by anonymous
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