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solve this $(2t^4 + 3t^3 - 2t^2 - 9t - 12) ÷( t^2 - 3)$

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Check whether the first polynomial is a factor of the second polynomial by dividing the second polynomial by the first polynomial : `t^2-3,""""2t^4+3t^3-2t^2-9t-12`
जांचें कि पहला बहुपद पहले बहुपद द्वारा दूसरे बहुपद को विभाजित करके दूसरे बहुपद का एक कारक है: `t^2-3,""""2t^4+3t^3-2t^2-9t-12`
0 answers asked Sep 2, 2020 in General Knowledge by anonymous
The slope of the tangent to the curve `x=t^2+3t-8,` `y=2t^2-2t-5` at the point `(2, " "1)` is (A) `(22)/7` (B) `6/7` (C) `7/6` (D) `(-6)/7`
वक्र के लिए स्पर्शक की ढलान `x=t^2+3t-8,` `y=2t^2-2t-5` बिंदु पर `(2, " "1)` एक है) `(22)/7` (बी) `6/7` (सी) `7/6` (डी) `(-6)/7`
0 answers asked Sep 2, 2020 in General Knowledge by anonymous
The solution set of the equation `4 sintheta.costheta-2costheta-2sqrt(3)sintheta +sqrt(3)=0` in the interval (0, 2T)ist (B) 13, 3 j (A) 4 4 (C) 4 3, 3 (D) All solutions of the equation 2 sino tann 0 ere obtained by taking a integral valuessof m and n in
समीकरण का समाधान सेट `4 sintheta.costheta-2costheta-2sqrt(3)sintheta +sqrt(3)=0` अंतराल (0, 2 टी) आईएसटी (बी) 13, 3 जे (ए) 4 4 (सी) 4 3, 3 (डी) समीकरण 2 सिनो टैन 0 के सभी समाधान एक अभिन्न मूल्यांकन एम और एन ले कर प्राप्त किया जाता है में
0 answers asked Sep 6, 2020 in General Knowledge by anonymous
Find the shortest distance between the following lines whose vector equations are: ` vec r=(1-t) hat i+(t-2) hat j+(3-2t) hat k` and ` vec r=(s+1) hat i+(2s-1) hat j-\ (2s+1) hat k` .
निम्नलिखित पंक्तियों के बीच सबसे छोटी दूरी खोजें जिनके वेक्टर समीकरण हैं: ` vec r=(1-t) hat i+(t-2) hat j+(3-2t) hat k` तथा ` vec r=(s+1) hat i+(2s-1) hat j- (2s+1) hat k` ।
0 answers asked Sep 3, 2020 in General Knowledge by anonymous
Let `f(x)=int_0^xcos((t^2+2t+1)/5)dt`, ` 0>x>2 then f(x)
चलो `f(x)=int_0^xcos((t^2+2t+1)/5)dt` , ` 0>x>2 then f(x) `
0 answers asked Sep 2, 2020 in General Knowledge by anonymous
Find the value of `x` such that `((x+alpha)^n-(x+beta)^n)/(alpha-beta)=(sin (ntheta))/(sin^n theta)`, where `alpha` and `beta` are the roots of the equation `t^2-2t+2=0`.
का मूल्य पाएं `x` ऐसा है कि `((x+alpha)^n-(x+beta)^n)/(alpha-beta)=(sin (ntheta))/(sin^n theta)` , कहा पे `alpha` तथा `beta` समीकरण की जड़ें हैं `t^2-2t+2=0` ।
1 answer asked Sep 2, 2020 in General Knowledge by anonymous
'd^(2t)'/'d^(-2t)'
'डी ^ (2t)' / 'd ^ (- 2t)'
0 answers asked Sep 2, 2020 in General Knowledge by anonymous
Simplify and solve the linear equations. `3(t-3)=5(2t+1)`
रैखिक समीकरणों को सरल और हल करें। `3(t-3)=5(2t+1)`
0 answers asked Sep 2, 2020 in General Knowledge by anonymous
Check whether the polynomial `q(t)=4t^3+4t^2-t-1` is a multiple of `2t+1`
जांच करें कि बहुपद है या नहीं `q(t)=4t^3+4t^2-t-1` का एक बहु है `2t+1`
0 answers asked Sep 2, 2020 in General Knowledge by anonymous
Find p(0), p(1) and p(2) for each of the following polynomials: (i) `p(y)=y^2-y+1` (ii) `p(t)=2+t+2t^2-t^3` (iii) `p(x)=x^3` (iv) `p(x)=(x-1)(x+1)`
निम्न में से प्रत्येक बहुपद के लिए पी (0), पी (1) और पी (2) खोजें: (i) `p(y)=y^2-y+1` (II) `p(t)=2+t+2t^2-t^3` (Iii) `p(x)=x^3` (Iv) `p(x)=(x-1)(x+1)`
0 answers asked Sep 2, 2020 in General Knowledge by anonymous
Find the Cartesian equation of the following planes: (a) ` -> rdot( hat i+ hat j- hat k)=2` (b) ` -> rdot(2 hat i+3 hat j-4 hat k)=1` (c) ` -> rdot[(s-2t) hat i+(3-t) hat j+(2s+t) hat k]=15`
निम्नलिखित विमानों के कार्टेशियन समीकरण खोजें: (ए) ` -> rdot( hat i+ hat j- hat k)=2` (ख) ` -> rdot(2 hat i+3 hat j-4 hat k)=1` (सी) ` -> rdot[(s-2t) hat i+(3-t) hat j+(2s+t) hat k]=15`
0 answers asked Sep 2, 2020 in General Knowledge by anonymous
Find the shortest distance between the lines whose vector equations are ` -> r=(1-t) hat i+(t-2) hat j+(3-2t) hat k` and ` -> r=(s+1) hat i+(2s-1) hat j-(2s+1) hat k`
जिन पंक्तियों के वेक्टर समीकरण हैं, उनके बीच सबसे छोटी दूरी पाएं ` -> r=(1-t) hat i+(t-2) hat j+(3-2t) hat k` तथा ` -> r=(s+1) hat i+(2s-1) hat j-(2s+1) hat k`
0 answers asked Sep 2, 2020 in General Knowledge by anonymous
If `3t a n At a n B=1,` prove that `2cos(A+B)=cos(A-B)dot`
अगर `3t a n At a n B=1,` साबित करो `2cos(A+B)=cos(A-B)dot`
0 answers asked Sep 6, 2020 in General Knowledge by anonymous
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