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In Figure, `X Pa n dX Q` are tangents from `X` to the circle with centre `OdotR` is a point on the circle. Prove that, `X A+A R=X B+B R`

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आकृति में, `X Pa n dX Q` से टैंगेंट हैं `X` केंद्र के साथ सर्कल के लिए `OdotR` सर्कल पर एक बिंदु है। साबित करो, `X A+A R=X B+B R`

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