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ई-मेल में cc कोलम का अर्थ है?

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If `A+B+C=pi` , prove that `cotA+cotB+cotC-cos e cAdotcos e cBdotcos e cC=cotAdotcotBdotcotCdot`
अगर `A+B+C=pi` , साबित करो `cotA+cotB+cotC-cos e cAdotcos e cBdotcos e cC=cotAdotcotBdotcotCdot`
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Show that: `|b+cc+a a+b q+r r+p p+q y+z z+**+y|=2|a b c p q r x y z|`
वो दिखाओ: `|b+cc+a a+b q+r r+p p+q y+z z+xx+y|=2|a b c p q r x y z|`
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By using properties of determinants. Show that: `|a^2+1a b a c a bb^2+1b cc a c b c^2+1|=(1+a^2+b^2+b^2)`
निर्धारकों के गुणों का उपयोग करके। वो दिखाओ: `|a^2+1a b a c a bb^2+1b cc a c b c^2+1|=(1+a^2+b^2+b^2)`
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Using the property of determinants and without expanding, prove that: `|a-bb-cc-a b-cc-a a-b c-a a-bb-c|=0`
निर्धारकों की संपत्ति का उपयोग और विस्तार के बिना, साबित करें कि: `|a-bb-cc-a b-cc-a a-b c-a a-bb-c|=0`
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Using the property of determinants and without expanding, prove that: `|-a^2a b a c b a b^2b cc a c b-c^2|=4a^2b^2c^2`
निर्धारकों की संपत्ति का उपयोग और विस्तार के बिना, साबित करें कि: `|-a^2a b a c b a b^2b cc a c b-c^2|=4a^2b^2c^2`
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Prove that `|b+c a a b c+a b cc a+b|=4a b c`
साबित करो `|b+c a a b c+a b cc a+b|=4a b c`
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